IBM Mainframe Forum

following is the error when I did without DCB info and with DCB of LRECL 474 in both the cases getting the same error.


WER108I SORTIN : RECFM=VB ; LRECL= 462; BLKSIZE= 27998
WER237I OUTREC RECORD LENGTH = 474
WER110I SORTOUT : RECFM=VB ; LRECL= 474; BLKSIZE= 27998
WER410B 7,848K BYTES OF VIRTUAL STORAGE AVAILABLE ABOVE THE 16MEG LINE,
WER410B 0 BYTES RESERVE REQUESTED, 2,264K BYTES USED
WER244A OUTREC - SHORT RECORD

Rather than us fixing your errors one by one, how about consulting your documentation/searching the web to find out what WER244A means? You could even just guess from the text of the message.

Yes BB, I am parellaly doing the same. my idea is that if some body might have faced the same issue can guide me.

You have "variable length records". But



Here you copy from position 44 for a length of 419 bytes. Not all your records are the full length. Your records are not fixed in length.

What you need is:



This, as the last definition on the statement, says "copy from start position 44 to the end of the current record". With that code, you'll not get a "short record" unless any records on your file are less than 44 bytes long.

Hello,

56+419 = 474

In which numbering system

d

Frictional losses

56+419 = 474, it is actully 475 but counting from the number of bytes from 56 to 419 it is 474 in length

some body can help me in this, is it possible with sync sort or is there any other way to achieve this

Well, excuse me,but it is bad manners to solicit responses apart from making an initial post. You have provided no indication that you have correctly implemented the last suggestion. Probably people are busy doing other things like their own jobs until you come back with a success/failure message.

I thought you were OK now.

Can you post your control cards, JCL, sysout from the step and let us know exactly what is wrong, please?