IBM Mainframe Forum

Need help on the below requirement -

I have a 12 digit number in that last 5 digits has to be incremented by +11. This needs to happen 10,000 times. Is there a way to do it using sort.
I am giving a example below -

12345678911 == example for first number based on this it should increment by 11 and generate 10, 000 numbers.
12345678922 == next number incremented by 11 (11 + 11 = 22)
12345678933 == next number incremented by 11 (22 + 11 = 33)
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Please help.

Thanks.

If there is only one record on your dataset, look at OUTFIL REPEAT= and SEQNUM on OVERLAY in your documentation.

If you have more than one record, please clarify your question.

Hi,

Nice Idea. Thanks.
Yes. Dataset has only one record (12345678911). how to use overlay in this situation please?

Thanks.

OK, the OVERLAY is quite easy. The next problem, though is that 10,000 times 11 gives a six-digit result, and you only want to change five digits. The answer to that impacts the detail of the OVERLAY.

Hi,

Thanks again. I won't mind to limit it to 9999 times to avoid this risk factor.

10,000 * 11 = 110,0000
9,999 * 11 = 10,9989
9,090 * 11 = 99.990

Even taking 9,090, unless the current number starts with nnn00000 to nnn00009 it will overflow the five low-order digits.