IBM Mainframe Forum

Step1 exec PROC1
Step2 Exec PROC2

IF PROC1 returns rc code 8 need to execute PROC1 until return code =0;
If rc= 0 then need to execute
Step2 EXEC PROC2

Is it possible to write jcl for above condition?

One word: NO. You cannot form loops in JCL.

What you can do is write JCL to resubmit the same job if the step is to run again.

How to do that? resubmit the same job ?

The last step (executed conditionally) is IEBGENER; SYSUT1 reads the JCL, SYSUT2 writes to the internal reader.

For goodness sake be very careful with that. If you get it wrong, a job which submits itself might get out-of-hand... check the CANCEL command, maybe, to see if it can kill all like-named jobs at once

BillyBoyo wrote:For goodness sake be very careful with that. If you get it wrong, a job which submits itself might get out-of-hand... check the CANCEL command, maybe, to see if it can kill all like-named jobs at once

Note that Viswa asked essentially the same question nine hours earlier and got essentially the same answers, plus a warning from Dr. Sorichetti that he was treading on forbidden ground (writing a DIY job scheduler). Somehow that thread escaped the TS's notice