IBM Mainframe Forum

How to find the current date in jcl ?

Suppose in DD step pds is defined with as &ddmmmyyyy parameter then how will we access the current file ?

Hello,

Plase post the entire dd statement.

JCL does not know the current date, but there is probably a way to accomplish what you want.

Suppose in DD step pds is defined with as &ddmmmyyyy parameter then how will we access the current file ?

Along with posting the dd statement, please clarify this.

If DD statement is
//DD DSN = DW.PROGRAM1.INFILE.&DDMMYYYY,DISP= SHR

So the file jcl should pick is the current file as file is created on daily basis with date extension by batch?

Hello,

That is what i was afraid of. . . An 8-digit number is invalid as a node of a dataset. You can verify this by removing the symbolic and putting in today's date to run a test. The job will raise a jcl error.

A better approach might be to make the file a gdg and create a +1 generation each day. When processing, the DW.PROGRAM1.INFILE(0) would be used with no need for the ddmmyyyy digits.