IBM Mainframe Forum

input:
001 123456
001 111111
001 222222
001 333333

output:
0001 12 456
0001 11 111
0001 22 222
0001 33 333

HI ALL, how to use OUTREL to get the output like above scenario ?
in the first byte + "0", and in the 7th byte = space

What version of JCL are you using? I just checked the JCL Language Reference manual - link above - and OUTREL is not found.

As NicC said, this is not properly a JCL question. JCL, by itself, cannnot manipulate data in any way.

More likely, it is a sort issue; I believe both DFSORT and Syncsort have an OUTREL control of some sort. Another possibility is to use IBM data set utilities. I think both the IEBGENER or IEBPTPCH utilities can be persuaded to edit your data in the way you want, though neither utility has an OUTREL control by that name.

If it is SORT, there are INREC, OUTREC and OUTFIL which can do that.



The C'...' notation is for character constants (there are other types you can look up). The X is a blank, 3X would be three blanks. There is others of those as well (see if you can find what Z does. 1,6 takes the first six from the input, and places them in the next available six from the output. 8.3 is similar.