IBM Mainframe Forum

by **Asad** » Thu Mar 27, 2008 3:28 pm

Hi,
I have a small code. Am not sure about the value of the variable. :

01 NUM1 PIC 9 VALUE ZERO.
Step1: ADD -2 TO NUM1

Execute Step1 3 TIMES

What will be the value of NUM1?

Please give clarification also.
Thanks

by **arunprasad.k** » Thu Mar 27, 2008 7:35 pm

Did you code this and ran?? What did you get in your output??

Didn't you get 2 as the result??

Arun.

by **qykong1986** » Fri Mar 27, 2009 7:28 am

I tried it on mainframe.

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05 WS-CHANGE-OUT PIC 9 VALUE ZERO.
...................
ADD -2 TO WS-CHANGE-OUT.
DISPLAY 'FIRST STEP ' WS-CHANGE-OUT.
ADD -2 TO WS-CHANGE-OUT.
DISPLAY 'SECOND STEP ' WS-CHANGE-OUT.
ADD -2 TO WS-CHANGE-OUT.
DISPLAY 'THIRD STEP' WS-CHANGE-OUT.

And the result :

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FIRST STEP 2
SECOND STEP 0
THIRD STEP 2

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