please answer anyone, help me. iam new to mainframes.
PERFORM ACCULATE-TOTALS VARYING A FROM 1 BY 2 UNTIL A > 2 AFTER B FROM 1 BY 1 UNTIL B > 2 AFTER C FROM 2 BY -1 UNTIL C < -9 How many times accumulate-totals will be executed?
a) 10
b) 09
c) 11
d) infinite loop.
How is sign stored in Packed Decimal fields?
a) Sign is stored as a hex value in the last nibble (4 bits ) of the storage
b) Sign is over punched with numeric value stored in the last bite
c) Sign is stored in hex value in first 4 bits of storage
d) None of the above