IBM Mainframe Forum

Hi All,

Here I am trying set the MAXTEMPS to be the size of current 4k workspace. The IBM manual says the DSNZPARM value accepts in MB but when I convert 4K it looks to be very small value as 0.00391 MB.

Apology If my value conversion is wrong. Could anyone please point me the right value for the 4K.

Jaggz

What happened when You checked with Your hand calculator ?

Dear Enrico,

Here the 4K is not 4KB, but its the size on disk of all the 4k datasets.(4K size of Block). So I am not sure how it is expressed in MB.

that' s not what You asked ...
even if it was what was implied by the numbers You posted !

4KB expressed in MB are just that ...
4096 / 1048576
which gives
4kb = 0.00390625

if You intended to ask a different question, since we do not read minds ,
You should have worded Your question in a different way

A new online updatable DSNZPARM, MAXTEMPS, has been added to DSN6SYSP. This DSNZPARM specifies the maximum amount of workfile storage that an agent can use and is specified in units of MBs or GBs. If the DSNZPARM value is specified as 0, then no limit is enforced, which was the default in previous releases.

So your original fraction of a megabyte is not going to work.

If what you are saying is the you have 4K (as a unit) of 4KB lumps, that would be 16MB don't you think? 4000 * 4KB = 16000KB = 16MB.